Go: returning from defer

In a deferred function you can alter the returned parameters, but you can’t return a new set. So a simple change to what you have will make it work.

There is another problem with what you wrote, namely that the you’ve paniced with a string but are expecting an error in your type assertion.

Here is a fix for both of those (Play)

defer func() {
    if r := recover(); r != nil {
        fmt.Println("Recovered in f", r)
        // find out exactly what the error was and set err
        switch x := r.(type) {
        case string:
            err = errors.New(x)
        case error:
            err = x
            err = errors.New("Unknown panic")
        // invalidate rep
        rep = nil
        // return the modified err and rep

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