From the documentation:
Struct values encode as JSON objects. Each exported struct field becomes a member of the object unless
- the field’s tag is “-“, or
- the field is empty and its tag specifies the “omitempty” option.
The empty values are false, 0, any nil pointer or interface value, and any array, slice, map, or string of length zero.
In your declaration of group
, it’s implicit that group.A
will be the zero value of the ColorGroup
struct type. And notice that zero-values-of-struct-types is not mentioned in that list of things that are considered “empty values”.
As you found, the workaround for your case is to use a pointer. This will work if you don’t specify A
in your declaration of group
. If you specify it to be a pointer to a zero-struct, then it will show up again.
package main
import (
"encoding/json"
"fmt"
"os"
)
func main() {
type colorGroup struct {
ID int `json:",omitempty"`
Name string
Colors []string
}
type total struct {
A *colorGroup `json:",omitempty"`
B string `json:",omitempty"`
}
groupWithNilA := total{
B: "abc",
}
b, err := json.Marshal(groupWithNilA)
if err != nil {
fmt.Println("error:", err)
}
os.Stderr.Write(b)
println()
groupWithPointerToZeroA := total{
A: &colorGroup{},
B: "abc",
}
b, err = json.Marshal(groupWithPointerToZeroA)
if err != nil {
fmt.Println("error:", err)
}
os.Stderr.Write(b)
}