I’m not familiar with either of these books, but the second is closer to current reality. The first may be discussing a specific processor. Processors have been made with quite a variety of word sizes, not always a multiple of 8. The 8086 and 8087 processors used 16 bit words, and it’s likely this is …
convert to base 2: var base2 = (yourNumber).toString(2); access the characters (bits): base2[0], base2[1], base2[3], etc…
An integer is represented as a sequence of bits in memory. For interaction with humans, the computer has to display it as decimal digits, but all the calculations are carried out as binary. 123 in decimal is stored as 1111011 in memory. The & operator is a bitwise “And”. The result is the bits that …
Something like this: SUM(CASE WHEN ColumnName = 1 THEN 1 ELSE 0 END) AS Pass, SUM(CASE WHEN ColumnName = 0 THEN 1 ELSE 0 END) AS Fail
These work for integers of any size, even greater than 32 bit: def set_bit(value, bit): return value | (1<<bit) def clear_bit(value, bit): return value & ~(1<<bit) If you like things short, you can just use: >>> val = 0b111 >>> val |= (1<<3) >>> ‘{:b}’.format(val) ‘1111’ >>> val &=~ (1<<1) ‘1101’
Convert.ToString(MyVeryOwnByte, 2).PadLeft(8, ‘0’); This will fill the empty space to the left with ‘0’ for a total of 8 characters in the string
Read the bits from a file, low bits first. def bits(f): bytes = (ord(b) for b in f.read()) for b in bytes: for i in xrange(8): yield (b >> i) & 1 for b in bits(open(‘binary-file.bin’, ‘r’)): print b
29 = 512 values, because that’s how many combinations of zeroes and ones you can have. What those values represent however will depend on the system you are using. If it’s an unsigned integer, you will have: 000000000 = 0 (min) 000000001 = 1 … 111111110 = 510 111111111 = 511 (max) In two’s complement, …
Another way to do this is by using the bitstring module: >>> from bitstring import BitArray >>> input_str=”0xff” >>> c = BitArray(hex=input_str) >>> c.bin ‘0b11111111’ And if you need to strip the leading 0b: >>> c.bin[2:] ‘11111111’ The bitstring module isn’t a requirement, as jcollado‘s answer shows, but it has lots of performant methods for …
Method 1: Use Integer.toBinaryString(a) where a is an Int. This method is from the Java platform and can be used in Kotlin. Find more about this method at https://docs.oracle.com/javase/7/docs/api/java/lang/Integer.html#toBinaryString(int) Note: This method works for both positive and negative integers. Method 2: Use a.toString(2) where a is an Int, 2 is the radix Note: This method …