#include <ifaddrs.h> #include <arpa/inet.h> // Get the INTERNAL ip address – (NSString *)getIPAddress { NSString *address = @”error”; struct ifaddrs *interfaces = NULL; struct ifaddrs *temp_addr = NULL; int success = 0; // retrieve the current interfaces – returns 0 on success success = getifaddrs(&interfaces); if (success == 0) { // Loop through linked list …
There are a few difference between the two: getCanonicalHostName() will attempt to resolve the FQDN. Therefore, you would get foo.mycompany.com whereas getHostName() might just return foo. getCanonicalHostName() will always do a reverse DNS lookup, whereas getHostName() would return the stored hostname if you supplied one in the InetAddress constructor. I suspect you will be wanting …
Sinatra provides a request object, which is the interface to the client request data that you should be using. Using request.ip is the preferred method to find the client’s IP address: get “https://stackoverflow.com/” do “Your IP address is #{request.ip}” end
You could use: Order Allow,Deny Deny from 66.249.74.0/24 Allow from all Or you could use this: RewriteEngine on RewriteCond %{REMOTE_ADDR} ^66\.249\.74\. RewriteRule ^ – [F]
I have found a class called DhcpInfo within the android.net package. It has some public variables that stores the values of current Network parameters. But the problem is they return the value in integer converted from 8Bit shifted binary. Sample Image Describing thee Scenario: ****Here is a sample code:** **java file:**** package com.schogini.dhcp; import android.app.Activity; …
From Jacob, Heroku’s Director of Security at the time: The router doesn’t overwrite X-Forwarded-For, but it does guarantee that the real origin will always be the last item in the list. This means that, if you access a Heroku app in the normal way, you will just see your IP address in the X-Forwarded-For header: …
Go to your client machine and type in: nslookup server.company.com substituting the real host name of your server for server.company.com, of course. That should tell you which DNS server your client is using (if any) and what it thinks the problem is with the name. To force an application to use an IP address, generally …
Take a look at IP Address Calculations with C# on MSDN blogs. It contains an extension method (IsInSameSubnet) that should meet your needs as well as some other goodies. public static class IPAddressExtensions { public static IPAddress GetBroadcastAddress(this IPAddress address, IPAddress subnetMask) { byte[] ipAdressBytes = address.GetAddressBytes(); byte[] subnetMaskBytes = subnetMask.GetAddressBytes(); if (ipAdressBytes.Length != subnetMaskBytes.Length) …
I’m assuming you want to match these ranges: 127. 0.0.0 – 127.255.255.255 127.0.0.0 /8 10. 0.0.0 – 10.255.255.255 10.0.0.0 /8 172. 16.0.0 – 172. 31.255.255 172.16.0.0 /12 192.168.0.0 – 192.168.255.255 192.168.0.0 /16 You are missing some dots that would cause it to accept for example 172.169.0.0 even though this should not be accepted. I’ve fixed …