I am reading a text file and want to use regex below to pull out numbers with exactly 5 digit, ignoring alphabets. Try this… var str=”f 34 545 323 12345 54321 123456″, matches = str.match(/\b\d{5}\b/g); console.log(matches); // [“12345”, “54321”] jsFiddle. The word boundary \b is your friend here. Update My regex will get a number … Read more
According to What’s New In Python 3.10, PEP 636, and the docs, you use a | between patterns: case ‘Egide’ | ‘Eric’:
To some extent, this is going to vary by the “flavour” of RegEx you’re using. The following is based on .NET RegEx, which uses \b for word boundaries. In the last example, it also uses negative lookaround (?<!) and (?!) as well as non-capturing parentheses (?:) Basically, though, if the terms always contain at least … Read more
There is the new smart match operator: #!/usr/bin/perl use 5.010; use strict; use warnings; my @x = (1, 2, 3); my @y = qw(1 2 3); say “[@x] and [@y] match” if @x ~~ @y; Regarding Array::Compare: Internally the comparator compares the two arrays by using join to turn both arrays into strings and comparing … Read more
$and with $match works just fine. You have syntax errors in your query. Try this. db.test.aggregate([ { $match: { $and: [ {type: {$in: [“TOYS”]}}, {type: {$nin: [“BARBIE”]}}, {time: {$lt:ISODate(“2013-12-09T00:00:00Z”)}} ] } } ]) And for what you are trying to do, you do not need an $and.
I would say that val is not a string. I get the val.match is not function error for the following var val=12; if(val.match(/^s+$/) || val == “”){ document.write(“success: ” + val); } The error goes away if you explicitly convert to a string String(val) var val=12; if(String(val).match(/^s+$/) || val == “”){ document.write(“success: ” + val); … Read more
This however will compile: def checkType(cls: AnyRef) { cls match { case s: String => println(“is a String”) case d: Date => println(“is a Date”) case _ => println(“others”) } } … or the simplified version of that: def checkType(cls: AnyRef) = cls match { case _: String => println(“is a String”) case _: Date … Read more
Presumably the EditText and the Button are inside a RelativeLayout. Set the button’s layout attributes to alignTop and alignBottom of the EditText.
How about something like this … var l1 = new List<int>() { 1,2,3,4,5,2,2,2,4,4,4,1 }; var g = l1.GroupBy( i => i ); foreach( var grp in g ) { Console.WriteLine( “{0} {1}”, grp.Key, grp.Count() ); } Edit per comment: I will try and do this justice. 🙂 In my example, it’s a Func<int, TKey> because … Read more