It looks like you are just determining if the draggables right intersects the targets left, and if the draggables top intersects the targets bottom (with some tolerance).
There are 2 ways I would go about this:
- Find all intersect elements and find the largest area – in this case the left square of the image below.
- If the draggable has the same dimensions as the droppable the 1/4 overlap would suffice – in this case the right square.
The second is by far the easiest to implement but is no means as general as the first.
So by having a quick look through your code, I would loop through all the “possible” droppable elements determine the area of the overlap and target the largest.