An example from msdn public struct Complex { double re, im; public override bool Equals(Object obj) { return obj is Complex c && this == c; } public override int GetHashCode() { return re.GetHashCode() ^ im.GetHashCode(); } public static bool operator ==(Complex x, Complex y) { return x.re == y.re && x.im == y.im; } … Read more
It’s hard to answer this sort of question precisely without spending an awful lot of time picking your words carefully. I’ve done so in a couple of articles which you may find useful: Parameter passing in C# / .NET Reference types and value types in C# / .NET That’s not to say that the articles … Read more
There is no difference between those two statements, and the optimiser will transform the IN to the = when IN has just one element in it. Though when you have a question like this, just run both statements, run their execution plan and see the differences. Here – you won’t find any. After a big … Read more
This is just operator precedence. Your first (1,) == 1, groups like so: ((1,) == 1), so builds a tuple with a single element from the result of comparing the one-element tuple 1, to the integer 1 for equality They’re not equal, so you get the 1-tuple False, for a result.
The JVM is caching Integer values. Hence the comparison with == only works for numbers between -128 and 127. Refer: #Immutable_Objects_.2F_Wrapper_Class_Caching
As others have said, it will only work when T is constrained to be a reference type. Without any constraints, you can compare with null, but only null – and that comparison will always be false for non-nullable value types. Instead of calling Equals, it’s better to use an IComparer<T> – and if you have … Read more