How to prevent phone numbers to be converted into Skype links?
Try not outputting the numbers as a single piece of text. Instead of <span>888-555-1212</span> try <span>888-</span><span>555-1212</span> and it will disable skype
Try not outputting the numbers as a single piece of text. Instead of <span>888-555-1212</span> try <span>888-</span><span>555-1212</span> and it will disable skype
go in skype->tools->options->advanced and UN-check use ports 80 & 443.
If your mobile site is (generally) used by iOS devices, you can use : <a href=”https://stackoverflow.com/questions/11598925/skype:YourSkypeName?call”>Call me on Skype</a> Apple iOS devices automatically recognizes intents in link with Skype and FaceTime.
Have you tried <a href=”https://stackoverflow.com/questions/2841676/skype:-skype-name-?chat”>Start chat</a> ? Allowed query parameters: chat – start a chat call – start a call add – add person to the contacts userinfo – view user’s profile voicemail – leave a voice message sendfile – send a file
This doesn’t seem to be very well documented, but there are ways to specify an action for a Skype profile link. This is the syntax skype:profile_name?action Examples of such actions are call to call chat to chat voicemail to leave a voice mail sendfile to send a file add to add to contacts userinfo to … Read more
In Skype: Go to Tools → Options → Advanced → Connections and uncheck the box use port 80 and 443 as alternative. This should help. As Salman Quader said: In the updated skype(8.x), there is no menu option to change the port. This means this answer is no longer valid.
To turn off and disable Skype usage of and listening on port 80 and port 443, open the Skype window, then click on the Tools menu and select Options. Click on the Advanced tab, and go to the Connection sub-tab. Untick or uncheck the checkbox for Use port 80 and 443 as an alternative for … Read more
If you mean a python script, just do something like this: Python 3.3+ use sys.modules and find_spec: import importlib.util import sys # For illustrative purposes. name=”itertools” if name in sys.modules: print(f”{name!r} already in sys.modules”) elif (spec := importlib.util.find_spec(name)) is not None: # If you choose to perform the actual import … module = importlib.util.module_from_spec(spec) sys.modules[name] … Read more