pthread_create and passing an integer as the last argument

Building on szx’s answer (so give him the credit), here’s how it would work in your for loop:

void *foo(void *i) {
    int a = *((int *) i);

int main() {
    pthread_t thread;
    for ( int i = 0; i < 10; ++1 ) {
        int *arg = malloc(sizeof(*arg));
        if ( arg == NULL ) {
            fprintf(stderr, "Couldn't allocate memory for thread arg.\n");

        *arg = i;
        pthread_create(&thread, 0, foo, arg);

    /*  Wait for threads, etc  */

    return 0;

On each iteration of the loop, you’re allocating new memory, each with a different address, so the thing that gets passed to pthread_create() on each iteration is different, so none of your threads ends up trying to access the same memory and you don’t get any thread safety issues in the way that you would if you just passed the address of i. In this case, you could also set up an array and pass the addresses of the elements.

Leave a Comment