Solution You can call the toObject method in order to access the fields. For example: var itemObject = item.toObject(); console.log(itemObject.title); // “foo” Why As you point out that the real fields are stored in the _doc field of the document. But why console.log(item) => { title: “foo”, content: “bar” }? From the source code of … Read more
Edit in 2021: This question was asked in 2010 when class was not available in JS. Nowadays, class has been so optimized that there is no excuse not to use it. If you need to use new, use class. But back in 2010 you had two options when binding methods to their object constructors — … Read more
It is never required to declare a prototype for a function in C, neither in “old” C (including C89/90) nor in new C (C99). However, there’s a significant difference between C89/90 and C99 with regard to function declarations. In C89/90 it was not necessary to declare a function at all. If the function is not … Read more
The C11 standard explicitly mentions these two: int main(void); int main(int argc, char* argv[]); although it does mention the phrase “or equivalent” with the following footnote: Thus, int can be replaced by a typedef name defined as int, or the type of argv can be written as char ** argv, and so on. In addition, … Read more
Prototypes are an optimisation. A great example of using them well is the jQuery library. Every time you obtain a jQuery object by using $(‘.someClass’), that object has dozens of “methods”. The library could achieve that by returning an object: return { show: function() { … }, hide: function() { … }, css: function() { … Read more
Update: ES6 now specifies Object.setPrototypeOf(object, prototype) . EDIT Feb. 2012: the answer below is no longer accurate. proto is being added to ECMAScript 6 as “normative optional” which means it isn’t required to be implemented but if it is, it must follow the given set of rules. This is currently unresolved but at least it … Read more
You cannot have an auto parameter. You basically have two options: Option #1: Use std::function as you have shown. Option #2: Use a template parameter: template<typename F> void f(F && lambda) { /* … */} Option #2 may, in some cases, be more efficient, as it can avoid a potential heap allocation for the embedded … Read more
All the other answers are correct, but just for completion A function is declared in the following manner: return-type function-name(parameter-list,…) { body… } return-type is the variable type that the function returns. This can not be an array type or a function type. If not given, then int is assumed. function-name is the name of … Read more