I believe you are correct. Here is an example of something I do, general navigation partial views in my Shared directory. and then a partial views for a specific Controller in the Views/[ControllerName] Directory.
You’re not actually passing the model to the Partial, you’re passing a new ViewDataDictionary<LetLord.Models.Tenant>(). Try this: @model LetLord.Models.Tenant <div class=”row-fluid”> <div class=”span4 well-border”> @Html.Partial(“~/Views/Tenants/_TenantDetailsPartial.cshtml”, Model) </div> </div>
Ruby allows you to do nice things like this: <%= render :partial => “foo/bar” if @conditions %> To make this a bit easier to read and understand, it can be written as: <%= render(:partial => “foo/bar”) if @conditions %> render is a function, and you pass it a hash that tells it which partial to … Read more
I had the same issue as the OP. From one of the comments, I realized that the second parameter shouldn’t be null, i.e from @model ParentViewModel @Html.Partial(“_Partial”, Model.Child) If Model.Child is null, then Model is passed instead of Model.Child. If there will be cases when the second parameter is null, then you will have to … Read more
Not without jQuery. What you would have to do is put your Partial in a div, something like: <div id=”partial”> @Html.Partial(“YourPartial”) </div> Then, to update (for example clicking a button with the id button), you could do: $(“#button”).click(function () { $.ajax({ url: “YourController/GetData”, type: “get”, data: $(“form”).serialize(), //if you need to post Model data, use … Read more
Create your partial view something like: @model YourModelType <div> <!– HTML to render your object –> </div> Then in your view use: @Html.Partial(“YourPartialViewName”, Model) If you do not want a strongly typed partial view remove the @model YourModelType from the top of the partial view and it will default to a dynamic type. Update The … Read more
It’s not necessary to use an underscore, but it’s a common convention for files which aren’t meant to be served directly. To solve this, you do have the option of returning a View or PartialView with the name of the view as a parameter. return View(“_List”); or return PartialView(“_List”); or inside another view @{ Html.RenderPartial(“_List”); … Read more
Ok, I am going to start over with a new answer here. Before you call $.validator.unobtrusive.parse, remove the original validator and unobtrusive validation from the form like so: var form = $(“#main_div”).closest(“form”); form.removeData(‘validator’); form.removeData(‘unobtrusiveValidation’); $.validator.unobtrusive.parse(form); This same answer is documented here.
Make sure your Model.UserProfile is not null. I found your post trying to debug the same error, and it turned out I hadn’t initialised my “Model.UserProfile” equivalent. I guess what’s happening here, is that if a null model is passed to RenderPartial, it defaults to using the main view’s model? Can anyone confirm this?
I know this had been asked a long time ago, but no one has shown an answer in this post. So I will do so here. To ensure everyone is on the same page, I will be verbose in my answer. I apologize in advance if it seems overly simplistic. In your server.js file (or … Read more