The pipe, |, is a special-character in regex (meaning “or”) and you’ll have to escape it with a \. Using your current regex: \|.*$ I’ve tried this in Notepad++, as you’ve mentioned, and it appears to work well.
cat yourfile.txt | tr -dc ‘[:alnum:]\n\r’ | tr ‘[:upper:]’ ‘[:lower:]’ The first tr deletes special characters. d means delete, c means complement (invert the character set). So, -dc means delete all characters except those specified. The \n and \r are included to preserve linux or windows style newlines, which I assume you want. The second …
Use re.search(): >>> import re >>> s1 = “thishasadigit4here” >>> m = re.search(r”\d”, s1) >>> if m: … print(“Digit found at position”, m.start()) … else: … print(“No digit in that string”) … Digit found at position 13
You’ll need to use a look behind assertion so that it isn’t included in the match: grep -Po ‘(?<=scheme_version”:)[0-9]+’
The more appropriate function here might be RegExp.test, which explicitly gives you true or false. console.log(/lolcakes/.test(“some string”)); // Output: false console.log(/lolcakes/.test(“some lolcakes”)); // Output: true
Update: <regex> is now implemented and released in GCC 4.9.0 Old answer: ECMAScript syntax accepts [0-9], \s, \w, etc, see ECMA-262 (15.10). Here’s an example with boost::regex that also uses the ECMAScript syntax by default: #include <boost/regex.hpp> int main(int argc, char* argv[]) { using namespace boost; regex e(“[0-9]”); return argc > 1 ? !regex_match(argv[1], e) …
It indicates that the subpattern is a non-capture subpattern. That means whatever is matched in (?:\w+\s), even though it’s enclosed by () it won’t appear in the list of matches, only (\w+) will. You’re still looking for a specific pattern (in this case, a single whitespace character following at least one word), but you don’t …
I have divided my answer into four sections. The first section contains my solution to the problem. Readers interested in nothing else may skip the other sections. The remaining three sections are concerned with identifying the pairs of equal digits that are preceded by a different digit and are followed by a different digit. The …
Try: /^(?!.*foobar)/.test(‘foobar@bar.de’) A (short) explanation: ^ # start of the string (?! # start negative look-ahead .* # zero or more characters of any kind (except line terminators) foobar # foobar ) # end negative look-ahead So, in plain English, that regex will look from the start of the string if the string ‘foobar’ can …
@match only works on the protocol/scheme, host, and pathname of a URL. To trigger off the query parameters, you can either use @include or use @match and also test the URL yourself. Note that the @match approach performs faster. With @include, you can use a regex syntax. See, also Include and exclude rules. In this …