It means “Rust compiler, infer what type goes into the Vec“. And it is indeed analogous to the unused variable in Python (and in Rust itself), in that it represents a placeholder for a type, like it can represent a placeholder for a variable name. You can find an explanation in The Rust Programming Language … Read more
Dart does not support instantiating from a generic type parameter. It doesn’t matter if you want to use a named or default constructor (T() also does not work). There is probably a way to do that on the server, where dart:mirrors (reflection) is available (not tried myself yet), but not in Flutter or the browser. … Read more
I have run into the same issue and found this article. In a nutshell you have this options: Make not generic wrapper class containing injected fields, make it to be a field of your class and inject it instead of generic class itself. Inject child non-generic class instead of base class. All annotated with @Inject … Read more
It seems to be a glitch. The Rust-analyzer LSP is able to infer what the type is supposed to be, but for whatever reason the compiler can’t. From what I can tell, this code doesn’t compile on any version of Rust, and cannot be automatically fixed with cargo fix. Interestingly, the compiler does seem to … Read more
As you’ve noted, impl AsRef<User> for User seems a little pointless since you can just do &user. You could do impl AsRef<String> for User or impl AsRef<u8> for User as alternatives to &user.email and &user.age but those examples are probably misuses of the trait. What does it mean to be able to convert a User … Read more
Similar to David Conrad solution, you can use the full signature as a link description, using syntax: {@link class#method(signature) text-to-display} Remember to escape < and >. For example: {@link #parse(Map, String, String) parse(Map<String, String>, String, String)}
Ok it seems you can do this: Foo<T extends IBar>() { /* */ } And that seems to make all calls require the T to implement IBar.
You can either add a type parameter to your struct, as in Zernike’s answer, or use a trait object. Using the type parameter is better for performance because each value of T will create a specialized copy of the struct, which allows for static dispatch. A trait object uses dynamic dispatch so it lets you … Read more
There is no generic constraint that allows you to enforce operator overload. You may take a look at the following library. Alternatively if you are using .NET 4.0 you could use the dynamic keyword: public static T Add<T>(T number1, T number2) { dynamic a = number1; dynamic b = number2; return a + b; } … Read more
Overloading is typically the bugaboo of type-inferenced languages (at least when, like F#, the type system isn’t powerful enough to contain type-classes). There are a number of choices you have in F#: Use overloading on methods (members of a type), in which case overloading works much like as in other .Net languages (you can ad-hoc … Read more