How to call a function inside $(document).ready

by

You are not calling a function like that, you just define the function.

The correct approach is to define the function outside document.ready and call it inside:

// We define the function
function validate(){
  console.log('validated!');
}

$(document).ready(function(){
  // we call the function
  validate();
});

Another option is to self invoke the function like that:

$(document).ready(function(){
   // we define and invoke a function
   (function(){
     console.log('validated!');
   })();
});

Leave a Comment