Use a nested list comprehension:

```
result = [a for tup in y for a in tup]
```

Example:

```
>>> x = range(10)
>>> y = [(i,j**2) for i,j in zip(x,x)]
>>> [a for tup in y for a in tup]
[0, 0, 1, 1, 2, 4, 3, 9, 4, 16, 5, 25, 6, 36, 7, 49, 8, 64, 9, 81]
```

This will work fine for your more general case as well, or you could do it all in one step:

```
y = [a for i in x for a in (i, sqrt(i), i**3, some_operation_on_i, f(i), g(i))]
```

In case the nested list comprehensions look odd, here is how this would look as a normal `for`

loop:

```
y = []
for i in x:
for a in (i, sqrt(i), i**3, some_operation_on_i, f(i), g(i)):
y.append(a)
```