You can use the command line tool dos2unix dos2unix input Or use the tr command: tr -d ‘\r’ <input >output Actually, you can do the file-format switching in vim: Method A: :e ++ff=dos :w ++ff=unix :e! Method B: :e ++ff=dos :set ff=unix :w EDIT If you want to delete the \r\n sequences in the file, … Read more
Use system from within awk: awk ‘{ system(“openssl s_client -connect host:port -cipher ” $1) }’ ciphers.txt
It’s easy, with GNU awk 4: zsh-4.3.12[t]% awk ‘{ for (i = 0; ++i <= NF;) printf “field %d => %s\n”, i, $i }’ FPAT='([^,]+)|(“[^”]+”)’ infile field 1 => filed1 field 2 => filed2 field 3 => field3 field 4 => “field4,FOO,BAR” field 5 => field5 Adding some comments as per OP requirement. From the … Read more
You can use the column command: me@home$ column -t output.txt CHAR.L 96.88 -6.75 (-6.49%) MXP.L 12.62 -1.00 (-7.41%) NEW.L 7.88 -0.75 (-8.57%) AGQ.L 17.75 -0.62 (-3.40%) RMP.L 13.12 -0.38 (-2.75%) RRR.L 3.35 -0.20 (-5.71%) RRL.L 7.95 -0.15 (-1.85%) SOU.L 1.73 -0.10 (-5.22%) YELL.L 5.47 -0.04 (-0.73%) AMC.L 9.75 -0.01 (-0.05%) PLU:USOP 95.40 0.00 (+0%) BP-.L … Read more
Try using: #!/usr/bin/awk -f as an interpreter
awk ‘{SUM+=$3}END{print SUM}’ where $3 represent value of column 3
Try grep -f the_ids.txt huge.csv Additionally, since your patterns seem to be fixed strings, supplying the -F option might speed up grep. -F, –fixed-strings Interpret PATTERN as a list of fixed strings, separated by newlines, any of which is to be matched. (-F is specified by POSIX.)
It sounds like you need sed: sed -n ‘/pattern/,/^$/p’ file Don’t print by default (-n). For lines that match /pattern/ up to an empty line /^$/, print.
The split seems unnecessary here, especially considering you’re using awk, which is made for field based processing. If your file is truly comma-separated, the following code seems much simpler, IMO: awk -F’,’ ‘{sum+=$57;} END{print sum;}’ file.txt For example, given the following input: ~$ cat testawk.txt a,a,aa,1 a,a,aa,2 d,d,dd,7 d,d,dd,9 d,dd,d,0 d,d,dd,23 d,d,dd,152 d,d,dd,7 d,d,dd,5 f2,f2,f2,5.5 … Read more
awk ‘{ if ($4 >= 1 && $4 <= 10) print $1 }’ sample.txt