grep -roh aaa . | wc -w Grep recursively all files and directories in the current dir searching for aaa, and output only the matches, not the entire line. Then, just use wc to count how many words are there.
You’ll need to use a look behind assertion so that it isn’t included in the match: grep -Po ‘(?<=scheme_version”:)[0-9]+’
The messages you are receiving is due to a lack of permission on those files, i.e., those are error messages. All you have to do is to redirect the stderr (standard error output) to /dev/null, like this: grep -irl “foo” 2> /dev/null To lear more about redirection (on bash), read this article: Bash Reference Manual …
You will get a nasty surprise when the number of files increase to more than one xargs command: Then you will first make a tar file of the first files and then overwrite the same tar file with the rest of the files. GNU tar has the –exclude option which will solve this issue: tar …
According to man grep page, -c flag is for -c, –count Suppress normal output; instead print a count of matching lines for each input file. So what you are seeing is the count of the match and not to be confused with the exit code of the grep match. The code 1 is because of …
Try: for a in [0-9]*.txt; do mv $a `printf %04d.%s ${a%.*} ${a##*.}` done Change the filename pattern ([0-9]*.txt) as necessary. A general-purpose enumerated rename that makes no assumptions about the initial set of filenames: X=1; for i in *.txt; do mv $i $(printf %04d.%s ${X%.*} ${i##*.}) let X=”$X+1″ done On the same topic: Bash script …
echo ‘first url, second url, third url’ | sed ‘s/.*second//’ Edit: I misunderstood. Better: echo ‘first url, second url, third url’ | sed ‘s/.*second \([^ ]*\).*/\1/’ or: echo ‘first url, second url, third url’ | perl -nle ‘m/second ([^ ]*)/; print $1’
The problem is that by default, you need to escape your |’s to get proper alternation. That is, grep interprets “foo|bar” as matching the literal string “foo|bar” only, whereas the pattern “foo\|bar” (with an escaped |) matches either “foo” or “bar”. To change this behavior, use the -E flag: tail -f logFile | grep -vE …
The command du tells you about disk usage. Example usage for your specific case: find rapidly_shrinking_drive/ -name “offender1” -mtime -1 -print0 | du –files0-from=- -hc | tail -n1 (Previously I wrote du -hs, but on my machine that appears to disregard find‘s input and instead summarises the size of the cwd.)
Consider checking this answer and that one. Also this might help you: grep certain file types recursively | commandlinefu.com. The command is: grep -r –include=”*.[ch]” pattern . And in your case it is: grep -r –include=”*.html” “onblur” .