The deep parsing of argument names is unique for PHP AFAIK. If you need just a simple list, just pass several parameters with the same name and use request.args.getlist(<paramname>) (documentation). Otherwise you have to parse the query string yourself.
This traverse generator function can be used to iterate over all the values: def traverse(o, tree_types=(list, tuple)): if isinstance(o, tree_types): for value in o: for subvalue in traverse(value, tree_types): yield subvalue else: yield o data = [(1,1,(1,1,(1,”1″))),(1,1,1),(1,),1,(1,(1,(“1”,)))] print list(traverse(data)) # prints [1, 1, 1, 1, 1, ‘1’, 1, 1, 1, 1, 1, 1, 1, ‘1’] …
Thanks for the quick and helpful answers guys! I just found another fast way to do this too: SELECT STUFF(( SELECT ‘,’ + X + ‘,’ + Y FROM Points FOR XML PATH(”) ), 1, 1, ”) AS XYList Credit goes to this guy: Link
If you’ve actually got a List<T>, I suggest you use List<T>.RemoveAll, after constructing a set of writer IDs: HashSet<long> writerIds = new HashSet<long>(listWriters.Select(x => x.WriterID)); articleList.RemoveAll(x => writerIds.Contains(x.WriterId)); anotherArticleList.RemoveAll(x => writerIds.Contains(x.WriterId)); If you do want to use LINQ, you could use: articleList = articleList.Where(x => !writerIds.Contains(x.WriterId)) .ToList(); anotherArticleList = anotherArticleList .Where(x => !writerIds.Contains(x.WriterId)) .ToList(); Note …
There is a shuffle method in the List class. The methods shuffles the list in place. You can call it without an argument or provide a random number generator instance: var list = [‘a’, ‘b’, ‘c’, ‘d’]; list.shuffle(); print(‘$list’); The collection package comes with a shuffle function/extension that also supports specifying a sub range to …
The method List.sort(comparator) that you are refering to was introduced in Java 8, whereas the utility method Collections.sort has been there since Java 1.2. As such, you will find a lot of reference on the Internet mentioning that utility method but that’s just because it has been in the JDK for a lot longer. Note …
You’re trying to concatenate a string and an integer, which is incorrect. Change print(numlist.pop(2)+” has been removed”) to any of these: Explicit int to str conversion: print(str(numlist.pop(2)) + ” has been removed”) Use , instead of +: print(numlist.pop(2), “has been removed”) String formatting: print(“{} has been removed”.format(numlist.pop(2)))
Use this: [[number+1 for number in group] for group in x] Or use this if you know map: [map(lambda x:x+1 ,group) for group in x]
From the Python FAQ: Lists and tuples, while similar in many respects, are generally used in fundamentally different ways. Tuples can be thought of as being similar to Pascal records or C structs; they’re small collections of related data which may be of different types which are operated on as a group. For example, a …