How to extract elements from a list using indices in Python? [duplicate]
Perhaps use this: [a[i] for i in (1,2,5)] # [11, 12, 15]
Perhaps use this: [a[i] for i in (1,2,5)] # [11, 12, 15]
Forget IEqualityComparer and just use Linq directly: EmployeeCollection.GroupBy(x => new{x.fName, x.lName}).Select(g => g.First());
[:] Shallow copies the list, making a copy of the list structure containing references to the original list members. This means that operations on the copy do not affect the structure of the original. However, if you do something to the list members, both lists still refer to them, so the updates will show up … Read more
You could solve this many ways. One that is pretty simple to understand is to just use a loop. def comp(list1, list2): for val in list1: if val in list2: return True return False A more compact way you can do it is to use map and reduce: reduce(lambda v1,v2: v1 or v2, map(lambda v: … Read more
you can use lst.pop() or del lst[-1] pop() removes and returns the item, in case you don’t want have a return use del
You mean this? num = 1234 lst = [int(i) for i in str(num)]
It is possible that this method signature was created as a by-product of some generic class. For example, SwingWorker has two type parameters, one for final result and one for intermediate results. If you just don’t want to use any intermediate results, you pass Void as the type parameter, resulting in some methods returning Void … Read more
So you want the difference between two lists of items. first_list = [[‘Test.doc’, ‘1a1a1a’, 1111], [‘Test2.doc’, ‘2b2b2b’, 2222], [‘Test3.doc’, ‘3c3c3c’, 3333]] secnd_list = [[‘Test.doc’, ‘1a1a1a’, 1111], [‘Test2.doc’, ‘2b2b2b’, 2222], [‘Test3.doc’, ‘8p8p8p’, 9999], [‘Test4.doc’, ‘4d4d4d’, 4444]] First I’d turn each list of lists into a list of tuples, so as tuples are hashable (lists are not) … Read more
In Python 3’s itertools there is a function called zip_longest. It should do the same as izip_longest from Python 2. Why the change in name? You might also notice that itertools.izip is now gone in Python 3 – that’s because in Python 3, the zip built-in function now returns an iterator, whereas in Python 2 … Read more
I think the easiest would be to write: var list = listOf(2,3) println(list) // [2, 3] list = listOf(1) + list println(list) // [1, 2, 3] There is no specific tail implementation, but you can call .drop(1) to get the same. You can make this head\tail more generic by writing these extension properties: val <T> … Read more