Django : Can’t import ‘module’. Check that module is correct

According to the documentation, is a full python path to the application. Full Python path to the application, e.g. ‘django.contrib.admin’. This attribute defines which application the configuration applies to. It must be set in all AppConfig subclasses. It must be unique across a Django project. Try this: class CoreConfig(AppConfig): name=”compfactu.core”

During handling of the above exception, another exception occurred

Currently, you are having an issue with raising the ValueError exception inside another caught exception. The reasoning for this solution doesn’t make much sense to me, but if you change it. raise Exception(‘Invalid json: {}’.format(e)) To raise Exception(‘Invalid json: {}’.format(e)) from None Making your end code. with open(json_file) as j: try: json_config = json.load(j) except …

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Python3 subprocess output

I suggest that you use subprocess.getoutput() as it does exactly what you want—run a command in a shell and get its string output (as opposed to byte string output). Then you can split on whitespace and grab the first element from the returned list of strings. Try this: import subprocess stdoutdata = subprocess.getoutput(“wc –lines /var/log/syslog”) …

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Reading named command arguments

You can use the Optional Arguments like so. With this program: #!/usr/bin/env python3 import argparse, sys parser=argparse.ArgumentParser() parser.add_argument(“–bar”, help=”Do the bar option”) parser.add_argument(“–foo”, help=”Foo the program”) args=parser.parse_args() print(f”Args: {args}\nCommand Line: {sys.argv}\nfoo: {}”) print(f”Dict format: {vars(args)}”) Make it executable: $ chmod +x Then if you call it with: $ ./ –bar=bar-val –foo foo-val It prints: …

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