For others who may be landing on this question, there was an additional step for me to get the default option to appear. In my case, the v-model I was binding to was returning null and rather than an empty string. This meant that the default option was never selected once Vue bindings kicked in. … Read more
select.list1 option.option2 { background-color: #007700; } <select class=”list1″> <option value=”1″>Option 1</option> <option value=”2″ class=”option2″>Option 2</option> </select>
The problem is that the CASE statement won’t work in the way you’re trying to use it. You can only use it to switch the value of one field in a query. If I understand what you’re trying to do, you might need this: SELECT ActivityID, FieldName = CASE WHEN ActivityTypeID <> 2 THEN (Some … Read more
SELECT * FROM mytable WHERE mycolumn REGEXP “\r\n”; finds all records in mytable where mycolumn contains a \r\n sequence.
If the first item is to be used as a placeholder (empty value) and your select is required then you can use the :invalid pseudo-class to target it. select { -webkit-appearance: menulist-button; color: black; } select:invalid { color: green; } <select required> <option value=””>Item1</option> <option value=”Item2″>Item2</option> <option value=”Item3″>Item3</option> </select>
Yes. It is possible 😀 SELECT SUM(totalHours) totalHours FROM ( select sum(hours) totalHours from resource UNION ALL select sum(hours) totalHours from projects-time ) s As a sidenote, the tablename projects-time must be delimited to avoid syntax error. Delimiter symbols vary on RDBMS you are using.
I wouldn’t push regular code into an exception block. Just check whether any rows exist that meet your condition, and proceed from there: declare any_rows_found number; begin select count(*) into any_rows_found from my_table where rownum = 1 and … other conditions … if any_rows_found = 1 then … else … end if;
Do you just want to search on word boundaries? If so a crude version might be: SELECT * FROM products WHERE product_name LIKE “% foo %”; Or you could be a bit cleverer and look for word boundaries with the following REGEXP SELECT * FROM products WHERE product_name RLIKE “[[:<:]]foo[[:>:]]”;
I’d use months_between, possibly combined with floor: select floor(months_between(date ‘2012-10-10’, date ‘2011-10-10’) /12) from dual; select floor(months_between(date ‘2012-10-9’ , date ‘2011-10-10’) /12) from dual; floor makes sure you get down-rounded years. If you want the fractional parts, you obviously want to not use floor.
What about the CONCAT() function? SELECT id, CONCAT(lastname, ‘, ‘, firstname) AS name FROM `table`; If you are going to concatenate many fields, you could also consider the CONCAT_WS() function, where the first argument is the separator for the rest of the arguments, which is added between the strings to be concatenated: SELECT id, CONCAT_WS(‘,’, … Read more