“Convert” Option[x] to x
If you have x as Option[Long], x.get will give you Long.
If you have x as Option[Long], x.get will give you Long.
This is a very interesting question and one that I don’t feel has a definitive answer, but I’ll do my best to throw my thoughts out there. Looking at the MVVM pattern as I understand it, the point of the ViewModel is to expose the data in a way the View can understand without any … Read more
In strings (or Unicode objects in Python 2), \u has a special meaning, namely saying, “here comes a Unicode character specified by it’s Unicode ID”. Hence u”\u0432″ will result in the character в. The b” prefix tells you this is a sequence of 8-bit bytes, and bytes object has no Unicode characters, so the \u … Read more
This behaviour has been filed as a bug on connect. This is a workaround: powershell ./test.ps1 -source test.ps1 -dest test.copy.ps1 -test:$true
Historical motivation: C The idea of integral promotions dates all the way back to pre-standard C. When providing arguments to variadic functions (…) or to functions without a prototype, promotions are applied. I.e. calling: // function declaration with no prototype void mystery(); // … char c=”c”; mystery(c); // this promotes c to int // in … Read more
You have 3 options: 1) Get default value dt = datetime??DateTime.Now; it will assign DateTime.Now (or any other value which you want) if datetime is null 2) Check if datetime contains value and if not return empty string if(!datetime.HasValue) return “”; dt = datetime.Value; 3) Change signature of method to public string ConvertToPersianToShow(DateTime datetime) It’s … Read more
Yes: In C++ (§4.5/4): An rvalue of type bool can be converted to an rvalue of type int, with false becoming zero and true becoming one. In C, when a value is converted to _Bool, it becomes 0 or 1 (§6.3.1.2/1): When any scalar value is converted to _Bool, the result is 0 if the … Read more
The third line of your code snippet: byte z = x + y; actually means byte z = (int) x + (int) y; So, there is no + operation on bytes, bytes are first cast to integers and the result of addition of two integers is a (32-bit) integer.
I was able to fix the error in React SASS using the calc function. font-size: calc(max(8vw, 30px));
You’ve run across Index signature is missing in type (only on interfaces, not on type alias) #15300 The code will work when you change an interface to a type: type Foo = { foo: number } const foo: Foo = { foo: 1 }; const bar: Record<string, unknown> = foo;