multipartform-data

Sending Multipart File as POST parameters with RestTemplate requests

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A way to solve this without needing to use a FileSystemResource that requires a file on disk, is to use a ByteArrayResource, that way you can send a byte array in your post (this code works with Spring 3.2.3): MultiValueMap<String, Object> map = new LinkedMultiValueMap<String, Object>(); final String filename=”somefile.txt”; map.add(“name”, filename); map.add(“filename”, filename); ByteArrayResource contentsAsResource … Read more

WebAPI File Uploading – Without writing files to disk

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Solved: Use the existing simple MultipartMemoryStreamProvider. No custom classes or providers required. This differers from the duplicate question which solved the solution by writing a custom provider. Then use it in a WebAPI handler as so: public async Task<IHttpActionResult> UploadFile() { if (!Request.Content.IsMimeMultipartContent()) { return StatusCode(HttpStatusCode.UnsupportedMediaType); } var filesReadToProvider = await Request.Content.ReadAsMultipartAsync(); foreach (var stream … Read more

simple HttpURLConnection POST file multipart/form-data from android to google blobstore

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use okhttp and use following snippet (taken from recipes) adjust the header values according to what your server expects. private static final String IMGUR_CLIENT_ID = “…”; private static final MediaType MEDIA_TYPE_PNG = MediaType.parse(“image/png”); private final OkHttpClient client = new OkHttpClient(); public void run() throws Exception { // Use the imgur image upload API as documented … Read more

Web API: how to access multipart form values when using MultipartMemoryStreamProvider?

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Updated 4/28/2015 You could create a custom provider based on MultipartFormDataRemoteStreamProvider. Example: public class CustomMultipartFormDataProvider : MultipartFormDataRemoteStreamProvider { public override RemoteStreamInfo GetRemoteStream(HttpContent parent, HttpContentHeaders headers) { return new RemoteStreamInfo( remoteStream: new MemoryStream(), location: string.Empty, fileName: string.Empty); } } Updated Custom In-memory MultiaprtFormDataStreamProvider: public class InMemoryMultipartFormDataStreamProvider : MultipartStreamProvider { private NameValueCollection _formData = new NameValueCollection(); private … Read more

Node.js (with express & bodyParser): unable to obtain form-data from post request

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In general, an express app needs to specify the appropriate body-parser middleware in order for req.body to contain the body. [EDITED] If you required parsing of url-encoded (non-multipart) form data, as well as JSON, try adding: // Put this statement near the top of your module var bodyParser = require(‘body-parser’); // Put these statements before … Read more

How to upload images to server in Flutter?

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Use MultipartRequest class Upload(File imageFile) async { var stream = new http.ByteStream(DelegatingStream.typed(imageFile.openRead())); var length = await imageFile.length(); var uri = Uri.parse(uploadURL); var request = new http.MultipartRequest(“POST”, uri); var multipartFile = new http.MultipartFile(‘file’, stream, length, filename: basename(imageFile.path)); //contentType: new MediaType(‘image’, ‘png’)); request.files.add(multipartFile); var response = await request.send(); print(response.statusCode); response.stream.transform(utf8.decoder).listen((value) { print(value); }); } name spaces: import … Read more

Using MultipartPostHandler to POST form-data with Python

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It seems that the easiest and most compatible way to get around this problem is to use the ‘poster’ module. # test_client.py from poster.encode import multipart_encode from poster.streaminghttp import register_openers import urllib2 # Register the streaming http handlers with urllib2 register_openers() # Start the multipart/form-data encoding of the file “DSC0001.jpg” # “image1” is the name … Read more

How can I receive an uploaded file using a Golang net/http server?

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Here’s a quick example func ReceiveFile(w http.ResponseWriter, r *http.Request) { r.ParseMultipartForm(32 << 20) // limit your max input length! var buf bytes.Buffer // in your case file would be fileupload file, header, err := r.FormFile(“file”) if err != nil { panic(err) } defer file.Close() name := strings.Split(header.Filename, “.”) fmt.Printf(“File name %s\n”, name[0]) // Copy the … Read more

Spring Controller @RequestBody with file upload is it possible?

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You can actually simplify your life here since all you are doing is submitting a form that contains some fields and file. You don’t need @RequestBody for what you are trying to do. You can use regular Spring MVC features, so your controller method would look like: @ResponseBody public WebResponse<Boolean> updateEUSettings( Locale locale, @Valid EUPSettingsWrapper … Read more