You cannot, but if they are the same length you can use the index from range. package main import ( “fmt” ) func main() { r1 := []int{1, 2, 3} r2 := []int{11, 21, 31} if len(r1) == len(r2) { for i := range r1 { fmt.Println(r1[i]) fmt.Println(r2[i]) } } } It returns 1 11 … Read more
awk ‘{ if ($4 >= 1 && $4 <= 10) print $1 }’ sample.txt
Enumerable.Range(1,12).Select(getMonthName);
It’s the splat operator. You’ll often see it used to split an array into parameters to a function. def my_function(param1, param2, param3) param1 + param2 + param3 end my_values = [2, 3, 5] my_function(*my_values) # returns 10 More commonly it is used to accept an arbitrary number of arguments def my_other_function(to_add, *other_args) other_args.map { |arg| … Read more
The easiest way to do that is use downto 5.downto(1) do |i| puts i end
Inside pattern match it can be expressed with guards: n match { case it if 0 until 5 contains it => “less than five” case it if 5 until 10 contains it => “less than ten” case _ => “a lot” }
JavaScript does have a Range object, but it refers to an arbitrary portion of the DOM and is not supported in IE 6/7. If you want, you can simplify your function to this, but it’s all the same really. this.years = function(startYear) { var currentYear = new Date().getFullYear(), years = []; startYear = startYear || … Read more
I would use enumerate as it’s more generic – eg it will work on iterables and sequences, and the overhead for just returning a reference to an object isn’t that big a deal – while xrange(len(something)) although (to me) more easily readable as your intent – will break on objects with no support for len…
SELECT * FROM generate_series(1, 6) num https://www.postgresql.org/docs/current/functions-srf.html